An ammeter with internal resistance 90 Ω Ω reads 1.85 A when connected in a circuit containing a battery and two resistors 700
and 410 Ω Ω in series. Actual current will be
Text Solution
Verified by ExpertsThe correct answer is:
B
In general, ammeter always reads less than the actual value because of its resistance.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In meter bridge or Wheatstone bridge for measurement of resistance, the known and the unknown resis…
A galvanometer can be converted into an ammeter by connecting
A cell of internal resistance 1.5 Ω Ω and of e.m.f. 1.5 volt balances 500 cm on a potentiometer wir…
10 -3 amp is flowing through a resistance of 1000 Ω Ω . To measure the correct potential difference…
A galvanometer of 100 Ω Ω resistance gives full scale deflection when 10 mA of current is passed. T…
50 Ω Ω and 100 Ω Ω resistors are connected in series. This connection is connected with a battery o…